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The /HEADERS options provides you with a lot more details on the program. For example, it is easy to see that section #1, .h3mf85n, is the code section. It is specified as Code, and the program s entry point resides in it (the entry point is at 404232 and .h3mf85n starts at 401000 and ends at 4042FF, so the entry point is clearly inside this section). The other oddly named section, .h477w81 appears to be a small data section, probably containing some variables. It s also worth mentioning that the subsystem flag equal 3. This identifies a Windows CUI (console user interface) program, and Windows will automatically create a console window for this program as soon as it is started. All of those oddly named sections indicate that the program is possible packed in some way. Packers have a way of creating special sections that contain the packed code or the unpacking code. It is a good idea to run the program in PEiD to see if it is packed with a known packer. PEiD is a program that can identify popular executable signatures and show whether an executable has been packed by one of the popular executable packers or copy protection products. PEiD can be downloaded from http://peid.has.it/. Figure 11.14 shows PEiD s output when it is fed with Defender.EXE. Unfortunately, PEiD reports Nothing found, so you can safely assume that Defender is either not packed or that it is packed with an unknown packer. Let s proceed to start disassembling the program and figuring out where that Sorry . . . Bad key, try again. message is coming from.

LIVES LOST 10 2 100 Marginally Accepted ANNUAL PROBABILITY OF FAILURE 10 1 10 2 Accepted 10 3 10 4 10 5 10 6 104 105 106 107 $ LOST 108 109 1010 Acceptable risk Suggested by Consultant March 1982

You pretend you are sailing up a narrow river. This needs three points (ideally a coach boat and two buoys forming a start line) to make a triangle. You must stay within the triangle; you can call water at the sides. This means that those boats that end up at the front have to tack every few boat lengths to stay in the triangle (river!)

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Because the program doesn t appear to directly call any APIs, there doesn t seem to be a specific API on which you could place a breakpoint to catch the place in the code where the program is printing this message. Thus you don t really have a choice but to try your luck by examining the program s entry point and trying to find some interesting code that might shed some light on this program. Let s load the program in IDA and run a full analysis on it. You can now take a quick look at the program s entry point.

.h3mf85n:00404232 .h3mf85n:00404232 .h3mf85n:00404232 .h3mf85n:00404232 .h3mf85n:00404232 .h3mf85n:00404232 .h3mf85n:00404233 .h3mf85n:00404235 .h3mf85n:00404236 .h3mf85n:00404237 .h3mf85n:00404238 .h3mf85n:00404239 .h3mf85n:0040423E .h3mf85n:0040423F .h3mf85n:00404244 .h3mf85n:00404249 .h3mf85n:0040424A .h3mf85n:0040424C .h3mf85n:0040424E .h3mf85n:00404253 .h3mf85n:00404255 .h3mf85n:00404257 start var_8 var_4 proc near = dword ptr -8 = dword ptr -4

Because of computational burdens, Baecher and Ingra used a very coarse mesh of 99 nodes and 320 triangular elements. The recent increases in computing power and reductions in cost make it possible to apply the methodology to more complicated problems. However, this has not been done to date.

push ebp mov ebp, esp push ecx push ecx push esi push edi call sub_402EA8 push eax call loc_4033D1 mov eax, dword_406000 pop ecx mov ecx, eax mov eax, [eax] mov edi, 6DEF20h xor esi, esi jmp short loc_404260 ; ----------------------------------------------------

Fenton and Grif ths (2002) used Monte Carlo simulation of correlated random elds to study the differential settlement of two strip footings of equal size placed on the surface of an elastic medium for which Young s modulus was logNormally distributed and spatially correlated. They showed that the expected value of the differential settlement ( ) is zero, but its variance depends on the correlation structure, the size of the footings, and their spacing. They proposed that assuming the differential settlement is approximately Normal and that the settlements of the two footings ( 1 and 2 ) are identically and log Normally distributed leads to = 0, 2 = 2(1 ) 2 (19.25)

Listing 11.6 A disassembly of Defender s entry point function, generated by IDA. (continued)

Exercise 5:

11

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