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No The language guarantees that operator delete() is not called by a delete expression if the pointer operand is set to 0 A test guarding against zero is always unnecessary (In fact, under most implementations, if you add the explicit test of the pointer, the test will, in effect, be carried out twice) It is important here to discuss the distinction between the lifetime of pi and that of the object to which pi refers The pointer pi itself is a global object declared in global scope As a result, the storage for pi is allocated before the program starts and lasts until the program ends This is different from the lifetime of the object addressed by pi, which is created when the new expression is encountered during the execution of the program The memory to which pi refers is dynamically allocated, and the object held within this memory is a dynamically allocated object pi is therefore a global pointer that refers to a dynamically allocated object of type int When the delete expression is encountered during the execution of the program, the memory to which pi refers is deallocated However, the memory for the pointer pi and its content are not themselves affected by the delete expression After the delete expression, pi is called a dangling pointer, that is, a pointer that refers to invalid memory A dangling pointer can be the source of program errors that are quite difficult to detect, and it is a good idea to set the pointer to 0 after the object it refers to has been deleted to make it clear hat the pointer points to no object A delete expression must be applied only to a pointer that refers to memory that has been allocated on the free store by a new expression Applying a delete expression to a pointer that does not refer to memory allocated on the free store is likely to result in undefined program behavior during execution of the program However, as we saw earlier, there is no penalty for applying a delete expression to a pointer of value 0 that is, a pointer that does not refer to any object The following are examples of safe and unsafe delete expressions:.

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walk(top [, topdown [, onerror [,followlinks]]]). Make ANSI/AIM . Using Barcode maker for Visual Studio .NET Control o generate, create EAN13 image in VS .NET applications. Creates a generator object that walks through directory tree top specifies the top of the directory, and topdown is a Boolean that indicates whether to traverse directories in a top-down (the default) or bottom-up orderThe returned generator produces tuples (dirpath, dirnames, filenames) where dirpath is a string containing the path to the directory, dirnames is a list of all subdirectories in dirpath, and filenames is a list of the files in dirpath, not including directoriesThe onerror parameter is a function accepting a single argument If any errors occur during processing, this function will be called with an instance of oserrorThe default behavior is to ignore errors If a directory is walked in a top-down manner, modifications to dirnames will affect the walking process For example, if directories are removed from dirnames, those directories will be skipped By default, symbolic links are not followed unless the followlinks argument is set to True.Related: 

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./WinDDK/resources/CPPPrimer/c++primerhtm. Make QR Code .Using Barcode creation for Java Control to generate, create barcode image in ava applications.allocates an array of ten string class objects from the free store, initializing psa with its address and then invoking the default string class constructor on each element of the array in turn One aspect of free store memory is that the objects allocated from it are unnamed The new expression does not return the actual allocated object but rather eturns the address of the allocated object All manipulation of the object is done indirectly through that address When our use of the object is complete, we must explicitly return the object's memory to the free store We do this by applying the delete expression to the pointer that addresses the object originally allocated through the new expression (The delete expression should not be applied to a pointer that addresses memory that has not been allocated by the new expression) For example:.Related: 

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Make Barcode In Visual Basic .NET Using Barcode drawer . In Visual Studio .NET Using Barcode drawer for .Both pointers hold the address of the string within the program free store, and we must be careful to apply delete to only one of the pointers The auto_ptr class template, on the contrary, supports the notion of ownership When we define pstr_auto, it recognizes its ownership of the string with which we initialize it and recognizes that it is responsible for deleting the string This is the responsibility that ownership confers upon an auto_ptr object The question is What happens in terms of ownership when pstr_auto2 is initialized to point to the same object as pstr_auto We don't want both auto_ptr objects to own the same underlying object that gives rise to all the problems of multiple deletions that we wanted to prevent by using the auto_ptr type in the first place When one auto_ptr object is initialized with or assigned to a second auto_ptr object, the left-hand auto_ptr object being initialized or assigned to now holds the ownership for the underlying object on the free store The right-hand auto_ptr object relinquishes all responsibility In our example, then, it is pstr_auto2 now that deletes the string object, and not pstr_auto, and pstr_auto can no longer be used to refer to the string object Similar behavior happens with the assignment operator Given the following two auto_ptr objects.Related: 

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The ABA problem stems from the fact that we use the pointer value of m_h e a d to determine whether the stack has changed But if nodes can be reused, it could be the case that after reading m_h e a d as a certain value X, the node X could be concurrently popped off the stack, subsequently reused, and then pushed back on the top of the stack as m_h e a d A thread doing an interlocked compare-exchange would then find the value X in the location and the CAS would succeed, because it appears as if the stack never changed Clearly this outcome is incorrect The CAS should have failed The list did change As a concrete example of why this can be a problem, imagine our stack has two nodes: X at the top, and Y just behind it Say a thread tries to pop X off and gets as far as reading its m_n ext pointer into a local variable, seeing Y But it doesn't get as far as executing the CAS, perhaps because it gets preempted by another thread-another thread, that pops X off and then Y, leaving the stack empty Yet another thread comes along, pushes a new node, Z, on, and then (for whatever reason) it pushes X on again If we pooled nodes, the object X might get reused time and time again, each time with a new value inside it At this point, X's m_n ext pointer will refer to Z But when the first thread resumes and performs its CAS, the operation will succeed: it will place Y as the new head-even though Y is long gone-and Z will now go completely missing This mysterious sequence of events is subtle enough to leave you frustrated and scratching your head Avoiding this problem typically requires additional state to be used in the CAS operation, such as a version number that is incremented upon each push and pop In other words, instead of updating one value, we will update two at once: the pointer and a new integer version number Implementing this either requires an extra layer of indirection, like using a separate object, or double CAS operations, such as a 64-bit CAS on a 32-bit machine or a 1 28-bit CAS on a 64-bit machine Since the latter isn't always available on all archi tectures, this makes writing efficient and portable ABA safe data structures difficult This situation won't happen in managed code (unless we explicitly pool nodes) because, unlike VC++, so long as a reference to an object is live the memory will not be reused This fact, coupled with integration of inter locked operations and the code that performs GCs, ensures ABA safety.

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2 Reading or writing to the object after it has been deleted This error can sometimes be detected by setting the pointer to 0 after deleting the object to which the pointer had pointed 3 Applying a delete expression to the same memory location twice This error can happen when two pointers address the same dynamically allocated object If delete is applied to one of the pointers, then the object's memory is eturned to the free store If we subsequently delete the second pointer, then the free store may be corrupted. Code Scanner In VS .NET Using Barcode scanner for .These kinds of errors in manipulating dynamically allocated memory are considerably easier to make than they re to track down and fix.Related: 

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